When you try to copy the value of one Array into another, you actually end up having two references to the same array. This is because an Array is a reference type.

int[] A = { 1, 2, 3 };
int[] B = A;
B[1] = 69;
Console.WriteLine(A[1]);

The above code would give an output of 69. As you can see, changes made to the elements of array B are applied to those of array A.

To do a copy by value you need to iterate through each of the Array elements in the source array and assign the value to the corresponding index in the destination array.

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int[] A = { 1, 2, 3 };
 
// Set the Size of Array B to be the same as that of Array A.
int[] B = new int[A.Length];
for (int I = 0; I < A.Length; I++)
{
    B[I] = A[I];
}

There is a much simpler way to do this using the static method Copy of the Abstract class Array.

int[] A = { 1, 2, 3 };
 
// Set the Size of Array B to be the same as that of Array A.
int[] B = new int[Arr.Length];
Array.Copy(A, 0, B, 0, Arr.Length);

The Copy method is overloaded into 4 forms with two variations:-

Array.Copy(int[] SourceArray, int[] DestinationArray, int NumberOfElementsToCopy);
Array.Copy(int[] SourceArray, int SourceIndexToStartCopyFrom,
int[] DestinationArray, int DestinationIndextToStartCopyFrom, int NumberOfElementsToCopy);

The remaining two forms are the long counterparts of these two.

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